A transportation worker takes a simple random sample of 162 toll booth receipts for one day and finds that the mean is $7.38 with a standard deviation of $1.45. What is the 99% confidence interval for the mean amount of all the receipts that day?

99% Confidence interval:  (7.09,7.67)

Step-by-step explanation:

We are given the following in the question:

Sample mean, = $7.38

Sample size, n = 162

Alpha, α = 0.05

Sample standard deviation, σ = $1.45

99% Confidence interval:  

Putting the values, we get,  

Degree of freedom = n - 1 = 161

is the required 99% confidence interval for the mean amount of all the receipts that day.

the volume is the product of the area of the base, 3x(3x+4), and the height, 3x-1

step-by-step explanation:

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