A rectangular school banner has a length of 36 inches and a width of 52 inches. A sign is made that is similar to the school banner and has a length of 22 inches. What is the ratio of the area of the school banner to the area of the sign

4212 : 1573 is the ratio.

Step-by-step explanation:

Given:

Length of rectangular school banner is 36 inches and width is 52 inches.

And, the sign made is similar to banner.

The sign's length is 22 inches.

Now, we have to find the ratio of the area of the banner to the area of the sign.

So, we have dimensions of rectangular school banner:

Length = 36 inches.

Width = 52 inches.

But, we have only length of sign:

Length = 22 inches.

Now, we have to find the width of sign by using cross multiplication method:

Let the width of sign be

As, sign is similar to banner.

So, if 36 inches is equivalent to 52 inches.

Then, 22 inches is equivalent to

By cross multiplying we get:

Dividing both sides by 36 we get:

Hence, the width of sign is inches.

Now, we find the area of banner and the area of sign by putting formula:

Area of banner = length × width.

Now, area of sign:

Now, to get the ratio of the area of the school banner to the area of the sign:

On simplifying we get:

Therefore, the ratio of the area of the school banner to the area of the sign is 4212:1573.

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse

step-by-step explanation:

i believe its "c" because all of the other options include a but it could be d because there is a way of financing with cash at certain places but its uncommon.