Suppose a company needs temporary passwords for the trial of a new payroll software. Each password will have two letters, followed by one digit, followed by one letter. The letter W will not be used. So, there are 25 letters and 10 digits that will be used. Assume that the letters can be repeated. How many passwords can be created using this format?

The answer is 156,250

There are 26 letters in the alphabet but you can not use W leaving 25.

There are 3 digits that will be letters and ten digits.

So the problem will be

= 25x25x10x25 = 156,250

Just tested on this and the answer was right.

Step-by-step explanation:

you need to give us more information since we can't answer

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: