Mathematics, 30.03.2020 16:39 Imamdiallo18

Listed below are the amounts of net worth (in millions of dollars of the ten wealthiest celebrities in a country. Construct a 95% confidence interval. What does the result tell us about the population of all celebrities? Do the data appear to be from a normally distributed population as required? 155 153 147 147 147 147 260 206 199 156 What is the confidence interval estimate of the population mean μ? S□ million su«s□ million (Round to one decimal place as needed.)

Answers: 3

Show answers

Answers

Using the appropriate statistical relation, the confidence interval estimate for the of netwworh of the wealthiest celebrities is (133.6 ; 209.8)

Given the samples :

X = 155 153 147 147 147 147 260 206 199 156

Using a calculator, we could obtain the sample mean and sample standard deviation :

Mean, μ = 171.7Standard deviation, σ = 38.06

The confidence interval can be defined thus :

Mean ± standard error Standard Error = Tcritical × σ/√nTcrit ; 95% ; df = n - 1 = 10 - 1 = 9 ; Tcritical = 2.26

Standard Error = (2.26 × 38.06/√10) = 27.20

Lower confidence boundary = 171.7 - 27.20 = 133.64

Upper confidence boundary = 171.7 + 27.20 = 209.76

Therefore, the confidence interval is (133.6 ; 209.8)

Learn more : link

Answer from: allycattt69

95% of confidence interval are (144.74 , 199.23)

Step-by-step explanation:

given data 155 153 147 147 147 147 260 206 199 156

given sample n =10

$mean = ∑x / n = \frac{155+ 153+ 147 +147+ 147= 147= 260+ 206 +199+ 156 }{10}$

mean = 171.7≅ 172

x x- mean (x-mean)^2

155 155-172= -17 289

153 153-172 = -19 361

147 147-172 = -25 625

260 260-172 = 88 7784

206 206-172 = 34 1156

199 199-172 = 27 729

156 156-172 = -16 256

∑ (x-mean)^2 = 13,075

Sample variance S^2 = ∑ (x-mean)^2 / n-1 = 13,075 / 10-1 =1452.77

sample standard deviation S = √variance = 38.11

95% confidence interval

The degrees of freedom = n-1 = 10-1 =9

The tabulated value 't' = 2.26 at '9' degrees of freedom at 95% level of significance

χ ± 2.26 S / √n

172 ± 2.26 (38.11)/√10

The intervals are (172 - 2.26 (38.11)/√10 , 172 + 2.26 (38.11)/√10)

( 172 - 27.236 , 172+27.236)

(144.74 , 199.23)

there fore the 95% of confidence interval are (144.74 , 199.23)

Answer from: Quest

step-by-step explanation:

i hate black

Answer from: Quest

it has changed from the width and the height.

step-by-step explanation:

Another question on Mathematics

Mathematics, 21.06.2019 13:30

Describe the possible echelon forms of the standard matrix for a linear transformation t where t: set of real numbers is onto.

Answers: 2

Answer

Mathematics, 21.06.2019 23:30

Afriend of mine is giving a dinner party. his current wine supply includes 10 bottles of zinfandel, 8 of merlot, and 11 of cabernet (he only drinks red wine), all from different wineries. (a) if he wants to serve 3 bottles of zinfandel and serving order is important, how many ways are there to do this? ways (b) if 6 bottles of wine are to be randomly selected from the 29 for serving, how many ways are there to do this? ways (c) if 6 bottles are randomly selected, how many ways are there to obtain two bottles of each variety? ways (d) if 6 bottles are randomly selected, what is the probability that this results in two bottles of each variety being chosen? (round your answer to three decimal places.) (e) if 6 bottles are randomly selected, what is the probability that all of them are the same variety? (round your answer to three decimal places.)

Answers: 3

Answer

Mathematics, 22.06.2019 02:30

In 1995 america online had about 3000000 users over the next decade users are expected to increase from a few million to the tens of millions suppose the number of users increased by 150% by the year 2000 how many users will there be in the year 2000

Answers: 3

Answer

Mathematics, 22.06.2019 03:00

The side of a square is 3 and 5/2 inches

Answers: 1

Answer

You know the right answer?

Listed below are the amounts of net worth (in millions of dollars of the ten wealthiest celebrities...

Questions