What is the equation process to this question?

Evaluate the function to answer the question.

The height h, in feet, of a ball that is released 4 ft above the ground with an initial upward velocity of 80 ft/s is a function of the time t, in seconds, the ball is in the air and is given by the following.

h(t) = −16t^2 + 80t + 4, 0 ≤ t ≤ 5.04

(a) Find the height of the ball (in feet) above the ground 2 s after its released.

(b) Find the height of the ball (in feet) above the ground 4 s after its released.

(a) Find the height of the ball (in feet) above the ground 2 s after its released.

That's just h(2)

h(2) = -16(2²) + 80(2) + 4 = -64 + 160 + 4 = 100

100 feet

(b) Find the height of the ball (in feet) above the ground 4 s after its released.

That's just h(4)

h(4) = -16(4²) + 80(4) + 4 = -256 + 320 + 4 = 68

68 feet

answer:  

step-by-step explanation:

here x represents the height of the pole,

and, the height of the shadow of the pole is 12 feet.

also, the angle of elevation from the top of the pole is 40°,

therefore,

by the low of sine,

which is the required equation for finding the value of x,