The safe load, L, of a wooden beam of width w, height h, and length l, supported at both ends, varies directly as the product of the width and the square of the height, and inversely as the length. A wooden beam 4 inches wide, 9 inches high, and 168 inches long can hold a load of 7900 pounds. What load would a beam 2 inches wide, 6 inches high, and 144 inches long, of the same material, support? (Round off your answer to the nearest integer.)

2257 pounds

Step-by-step explanation:

First, get the volume of each and since density is the same, we shall use the density to get the other mass

First volume

Volume=lwh where l is length, w is width and h is height.

Substituting with the given figures

Volume=4*9*168=6048

Density

Density is mass per unit volume

D=m/v

Mass is given as 7900 pounds

Density is 7900/6048=1.3062169312169

Volume of second box

V=2*6*144=1728

Mass is product of volume and density hence 1.3062169312169*1728=2257.1428571428 pounds

Rounded off as 2257 pounds

choice b is correct

step-by-step explanation:

we have been given the following system of inequalities;

we are required to graph the solution to the system of inequalities. using a graphing tool, the graph of the system is as shown in the attachment. the continuous line represents the graph of while the dotted line represents .

answer is 12345678900987654321234567890987654321

step-by-step explanation: