Mathematics, 29.03.2020 21:26 ramentome7542

A football team games 3 yd on the 1st game play loses 6 yd in the 2nd game play loses 4 yd in the 3rd game played and games 5 yd in the 4th game play. What is the teams over gain or lost for all 4 games

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Answer from: yeehaw777

The overall loss in the four games of the team = 2

Step-by-step explanation:

Gain in the first game = 3 yd

Loss in the second game = - 6 yd

Loss in the third game = - 4 yd

Gain in the fourth game = 5 yd

Total gain of the game = 3 + 5 = 8 yd

Total loss in the game = - 6 - 4 = - 10 yd

Since gain is less than the loss so overall loss in the game = 8 - 10 = - 2

Therefore the overall loss in the four games of the team = 2

Answer from: mlguerrero12

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Answer from: Quest

location: point 0

step-by-step explanation:

well, -8 to 10 on a number line is 18 spaces.

1/9 of 18 is 2.

so, 4/9 of 18 must be 8.

8 spaces from -8 (a) is 0.

so, 4/9 of the way from -8 to 10 is 0!

Answer from: Quest

the least common denominatore of 7 and 2 is 9

step-by-step explanation:

7+2=9

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