A ladder 7 m long is leaning against a wall. If the bottom of the ladder is pushed horizontally toward the wall at 1.5 m/s, how fast is the top of the ladder sliding up the wall when the bottom is 2 m from the wall?

Therefore the top of the ladder sliding up the wall the bottom is 2 m from the wall is 0.45 m/s.

Step-by-step explanation:

Given that a ladder is 7 m long.

Let the distance the wall and the bottom of the ladder be x.

and the distance of the ground to the top of the ladder where it touches the wall be y.

The length of the ladder be L which is constant.

The ladder is inclination against a wall. So it will from a right angled triangle whose base = x, height = y and hypotenuse = L.

By the Pythagorean Theorem,

x²+y²=L².....(1)

Differentiating with respect to t

......(2)         [Since L= 7 m is a constant]

The bottom of the ladder is pushed horizontally towards wall at 1.5 m/s.

It means m/s. [ Since it is decrease]

When the bottom of the ladder is 2 m away from the wall, Then the tip of the ladder is y.

Putting x=2 and L=7 in equation (1) we get

Now putting the value of x=2, y and  in equation (2)

(approx)

Therefore the top of the ladder sliding up the wall the bottom is 2 m from the wall is 0.45 m/s.

b) well because you get well

step-by-step explanation:

hans did not square the 40-unit side; he merely multiplied it by 2.   incorrect.