Acos²theta + Bsin²theta = C
Show that
tan²theta =C- A/B-C

Step-by-step explanation:

Here we have  , Acos²theta + Bsin²theta = C or ,

Let theta = x , So   . Let's solve it further

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Therefore ,   .

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length