Solve for
r
rr.
12
−
1
5
r
=
2
r
+
1
12−
5
1

r=2r+112, minus, start fraction, 1, divided by, 5, end fraction, r, equals, 2, r, plus, 1
r
=

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.