The riverside geyser in Yellowstone erupts about every 6.25 h. When the geyser erupts, the water has an initial upward velocity of 69 ft /s. What is maximum height of the geyser?

Correct  Hmax = 22.11 m

Step-by-step explanation:

The subject of this problem is a vertical shot upwards, to which the following formula applies:

V₀² - V² = 2 · g · H   where is:

V₀ - initial velocity

V - final velocity

g = 10 m/s²

H - final height

Given:

V₀ = 69 ft/s = 21.03 m/s

V = 0 m/s

Hmax = ?

V₀² = 2 · g · Hmax  ⇒ Hmax = V₀² / 2 · g

Hmax = 21.03² / 2 · 10 = 442.26 / 20 = 22.11 m

Hmax = 22.11 m

God is with you!!!

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.