Use substitution to find the common solution of these equations

A) y=2x and y=x-4
B) y=x+6 and y=3x
C) y=-3x and x-4
D) y=x/3 and y=x+4

pls help will be giving brainpower if u can answer all four~-~ also 25 points

Step-by-step explanation:

to solve this system of equation using substitution method

A) y=2x and y=x-4

let

y=2x equation 1

y=x-4 equation2

substitute equation 1 into equation 2

y=x-4 equation2

2x = x - 4

collect the like terms

2x - x = -4

x = -4

put x = -4 into equation 1

y=2x equation 1

y= 2(-4)

y = -8

therefore  x = -4 and y = -8.

question B

let

y=x+6 equation1

y=3x equation2

substitute equation 2 into equation 1

y=x+6 equation1

x + 6 = 3x

6 = 3x -x

6 = 2x

divide both sides bu the coefficient of x which is 2

6/2 = 2x/2

x = 3

put x = 3  into equation 2

y=3x equation2

y = 3(3)

y = 9

therefore x and y is 3 and 9 respectively

QUESTION C

let

y= -3x equation 1

y= x-4 equation 2

substitute for equation 1 in equation 2

y= x-4 equation 2

-3x = x- 4

collect the like terms

-3x - x  = -4

-4x = -4

divide both sides by -4

-4x/-4 = -4/-4

x = 1

put the value of x = 1 into equation 1

y= -3x equation 1

y = -3(1)

y = -3

therefore the value of x and y i this system of equation is 1 and -3 respectively.

QUESTION D

let

 y=x/3 equation 1

y=x+4 equation 2

substitute equation 1 into equation 2

y=x+4 equation 2

x/3 = x + 4

multiply through by 3

x = 3x + 12

collec the like terms

x - 3x = 12

-2x = 12

divide both sides by -2

-2x/-2 = 12/-2

x = -6

put the value of x = -6 into equation 1

 y=x/3 equation 1

y = -6/3

y = -2

therefore the value of x and y is -6 and -2 respectively.

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