Two buses leave the bus terminal at 4pm. The first bus completes its route in 20 minutes. The second bus its route in 35 minutes. At what time will they be back at the bus terminal together again?

The answer to your question is 6 h 20 min or 18:20

Step-by-step explanation:

Data

Initial time = 4 pm

1st route = 20 min

2nd route = 35 min

Process

1.- Calculate the Least common factor (LCF)

                     20  35   2

                      10  35   2

                        5  35  5

                         1    7  7

                               1

LCF = 2 x 2 x 5 x 7

       = 140 min  

2.- Convert the minutes to hours

          140 /60 = 2 hours 20 min

3.- Calculate the hour when the two buses will meet again

             4 pm + 2h20 min = 6 h 20 min  or 18:20

1 + (6 / x - 1)

step-by-step explanation:

divide using polynomial division.

add the numbers under frequency to find the total number:

5 + 8 +7 + 4 + 0 +1 = 25

the answer is 25.