I really dont understand how to start with this?

You could determine the quadratic approximation of the curve near which gives you a good estimate since the function is relatively monotone.

First calculate the second derivative,

Then write down the quadratic approximation,

That yields,

Of course this can be further simplified but its not obligatory.

Hope this helps.

f(x) = x² + (10/3)(x^1.5) - 6/x - 10sqrt(3)

Step-by-step explanation:

f'(x) is the derivative of f(x)

To go back to f(x), integrate f'(x)

f'(x) = 2x + 5(x^0.5) + 6(x^-2)

Add 1 to the power, divide by the new power

2(x^2)/2 + 5(x^1.5)/1.5 + 6(x^-1)/-1

f(x) = x² + (10/3)(x^1.5) - 6/x + c

Find c using (3,7)

7 = 3² + (10/3)(3^1.5) -6/3 + c

7 = 9 + 10sqrt(3) - 2 + c

c = - 10sqrt(3)

f(x) = x² + (10/3)(x^1.5) - 6/x - 10sqrt(3)

angle q= 92 degree

step-by-step explanation:

the solution is in the picture

when a quadrilateral is inscribed in a circle, the opposite angles are supplement to each other. in other words, the sum of the 2 angle is 180 degree

the answer to your question a or b but i am pretty sure it is b. i hope this : )

step-by-step explanation: