Americans spend an average of 4 hours per day online. If the standard deviation is 26 minutes, find the range in whitch at least 88.89% of the data will lie. Use Chebyshev's theorem. Round your K to the nearest whole number.

The range in which at least 88.89% of the data will lie is (162,318).

Step-by-step explanation:

Given:

Average time spend online, = hrs = mins

Standard deviation, = mins

We have to find the range in which at least 88.89% of the data will lie by using Chebyshev's theorem :

Formula :

Lower range =

Higher range =

Now we have to find k values.

We know that the percentage of the data that lies within 'k' standard deviation is at least,1-1/k^2 and k > 1.

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Plugging the value of k=3 in the formula above.

The range is .

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So,

The range in which at least 88.89% of the data will lie is (162,318).

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step-by-step explanation: