The volume of cube A is 216 cubic inches. The length of each edge in cube B is 2 inches longer than the length of each edge in cube A. How much greater is the volume of cube B than the volume of cube A.

296 cubic in.

Step-by-step explanation: Since we are talking about cubes, and you know the volume of a cube is lwh, we know l, w and h are all equal, meaning be can cube root the volume to find all side lengths. The cube root of 216 is 6, so if each side in cube B is 2 longer, then the lwh for B is 8*8*8, or 512. 512-216=296.

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt

wow ok so the answer is 1k or just k

because of combining like terms xd