Box A can hold 10 marbles. Box B is double the height of Box A, four times the length of Box A, and half the width of box A. How many marbles can Box B hold?

40 marbles.

Step-by-step explanation:

Given:

Box A can hold 10 marbles.

Box B is double the height of Box A, four times the length of Box A, and half the width of box A.

Question asked:

How many marbles can Box B hold?

Solution:

Let volume of box A =

Let volume of box B =

Now, suppose:

Length of box A =

Breadth =

Height =

So, volume of box A,

As given, Box B is double the height of Box A, four times the length of Box A, and half the width of box A.

So, Length of box B =

     Breadth =

     Height =

Volume of box B, =

By dividing volume of box A with volume of box B:

By cross multiplication:

That means volume of box B is 4 times volume of box A;

∵ Box A can hold = 10 marbles

∴ Box B ( 4 times of box A ) can hold =

Therefore, Box B can hold 40 marbles.

muyb ajo

step-by-step explanation:

jegosu

c.   x=2.4cm

step-by-step explanation:

similar triangles are triangles which have the same shape but not the same size. this means their angle measures are equal but their side lengths are not instead they are proportional. to solve, we will set up a proportion and solve.

a proportion is two equal ratios set equal to each other. we form the ratios by finding corresponding sides (sides which match to each other on both triangles by their position). out ratios will be one side of the small triangle over the corresponding side on the big triangle as shown below:

.

to solve the proportion, we'll cross multiply by multiplying numerator with denominator across the equal sign.