If 5y = 6x + 16 and 9x = 7y -20, what is the value of 3x - 2y?

16

Step-by-step explanation:

5y=6x+16...(I) and 9x=7y-20(ii)

Using substitution method:

Multiply equation ii by 5

45x=35y-100

Substitute (I) into ii

45x=7 * 5y - 20

45x=7(6x+16)

45x=42x+112

45x-42x=112

3x=112……

5y=6x+16

5y=2*3x+16

5y=2*112+16

5y=224+16

5y=240

Divide both sides by 5

y=48

3x-2y

112-2*48

112-96

16

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)