Contestants in the Run-and-Bike-a-thon run for a specified length of time, then bike for a specified length of time. Jason ran at an average speed of 5.8 mi/h and biked at an average speed of 20.2 mi/h, going a total of 14.6 miles. Seth ran at an average speed of 11.6 mi/h and biked at an average speed of 18.8 mi/h, going a total of 17 miles. For how long do contestants run and for how long do they bike? Round to the nearest hundredth if necessary.

The contestants run for 0.55 hour and they bike for 0.565 hour.

Step-by-step explanation:

Since we have given that

Let the time taken for running be x and the time taken for biking be y

Average speed of running by Jason = 5.8 mi/h

Average speed of his bike = 20.2 mi/h

Total distance = 14.6 miles,

So, it becomes,

--------------------(1)

Average speed of running by Seth = 11.6 mi/h

Average speed of his bike = 18.8 mi/hr

Total distance = 17 miles

------------------(2)

So, From Eq(1), and (2), we get that

x=0.55 and y = 0.565

Hence, the  contestants run for 0.55 hour and they bike for 0.565 hour.

plz yuo

step-by-step explanation:

i believe it is c.y = 9x

rise over run. 9 units up over 1 unit right or 9/1