FINANCE

Luke could invest $1000 at simple interest rate of 11% p. a. for 4 years or at 10% p. a. compound interest for the same period of time. Which is the better investment and by how much?

Pls show full working out ty ;)

Step-by-step explanation:

Simple interest rate = 1000(1+11x4) = 4500

= 4500-1000=3500

Comppound interest rate = 100%+10%=110%/100%=1.1%

1000X(1.1)^4=1464.10

2x^2+5x+17

your welcome. : )

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752