Jose invests $10900 in two different accounts. The first account paid 8 %, the second account paid 11 % in interest. At the end of the first year he had earned $1052 in interest. How much was in each account?

$ at 8 %

$at 11 %

$4900 at 8%

$6000 at 11%

Step-by-step explanation:

Let x represent the amount which he invested in the account paying 8% interest.

Let y represent the amount which he invested in the account paying 11% interest.

Jose invests $10900 in two different accounts. The first account paid 8 %, the second account paid 11 % in interest. This means that

x + y = 10900

The formula for determining simple interest is expressed as

I = PRT/100

Considering the account paying 8% interest,

P = $x

T = 1 year

R = 8℅

I = (x × 12 × 1)/100 = 0.08x

Considering the account paying 11% interest,

P = $y

T = 1 year

R = 11℅

I = (y × 6 × 1)/100 = 0.11y

At the end of the first year he had earned $1052 in interest., it means that

0.08x + 0.11y = 1052 - - - - - - - - - -1

Substituting x = 10900 - y into equation 1, it becomes

0.08(10900 - y) + 0.11y = 1052

872 - 0.08y + 0.11y = 1052

- 0.08y + 0.11y = 1052 - 872

0.03y = 180

y = 180/0.03

y = 6000

x = 10900 - y = 10900 - 6000

x = 4900

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

the answer would be 150 books

step-by-step explanation:

if you divide 300 by 2 you will get 150