Solve the system of equation by the addition method x-2y=11 and -x+6y =-31

x = 1, y = - 5

Step-by-step explanation:

The given system of linear equations is expressed as

x - 2y = 11- - - - - - - - - - - - -1

- x + 6y = - 31- - - - - - - - - - - -2

We would eliminate x by adding equation 1 to equation 2. It becomes

- 2y + 6y = 11 - 31

4y = - 20

Dividing the the left hand side and the right hand side of the equation by 4, it becomes

4y/4 = - 20/4

y = - 5

Substituting y = - 5 into equation 1, it becomes

x - 2 × - 5 = 11

x + 10 = 11

Subtracting 10 from the left hand side and the right hand side of the equation, it becomes

x + 10 - 10 = 11 - 10

x = 1

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

step-by-step explanation: