A college student with a bachelors degree in nursing from an accredited institution has an 86.74% chance of getting hired full time in a hospital setting within 6 months of graduation. There is a 34.72% chance of a student interested in a nursing degree not making it through the program due to not meeting GPA requirements, finding another health science track they'd rather complete, or various other reasons. Compute the probability of a Madonna University nursing student getting hired within 6 months of graduation given that they complete their degree here.

86.74% probability of a Madonna University nursing student getting hired within 6 months of graduation given that they complete their degree here.

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

In which

P(B|A) is the probability of event B happening, given that A happened.

is the probability of both A and B happening.

P(A) is the probability of A happening.

Compute the probability of a Madonna University nursing student getting hired within 6 months of graduation given that they complete their degree here.

In this problem, we have that:

Event A: Completing their degree there.

There is a 34.72% chance of a student interested in a nursing degree not making it through the program.

So 100 - 34.72% = 65.28% = 0.6528 probability of completing their degree. So P(A) = 0.6528.

Event B: Getting hired

86.74% chance of getting hired full time in a hospital setting within 6 months of graduation.

Completing their degree and getting hired:

Probability:

86.74% probability of a Madonna University nursing student getting hired within 6 months of graduation given that they complete their degree here.

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.