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In ΔABC, sin A=82, sin B=58, and b=27. Find the length of A.

The dimension of A is 38.17

Step-by-step explanation:

Using the sine law

a/sin A = b/ sin B

For the question In ΔABC, sin A=82, sin B=58, and b=27. Find the length of A.

a/sin A = b/ sin B

Sin A = 82

b = 27

Sin B = 58

a/ 82 = 27/58

58a = 27 ×82= 2214

a = 2214/58 = 38.1724= 38.17

31.5

Step-by-step explanation:

a/sinA = b/sinB

a/sin(82) = 27/sin(58)

a = 31.52797345

just watch memes

step-by-step explanation:

it me < 3

an = 22 + (n-1) *6

110 seats

step-by-step explanation:

an=a1+(n-1)(d)

a1 = 22   this is the first item in the sequence

d =6   this is how the sequence goes up

a)   an = 22 + (n-1) *6

b) a12 = 22 + (12-1) *6

    a12 = 22+11*6

  a12 = 22 +88

  a12 = 110