An article reported that, in a study of a particular wafer inspection process, 356 dies were examined by an inspection probe and 150 of these passed the probe. Assuming a stable process, calculate a 95% (two-sided) confidence interval for the proportion of all dies that pass the probe. (Round your answers to three decimal places.)

The 95% (two-sided) confidence interval for the proportion of all dies that pass the probe is (0.37, 0.472)

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.

In which

z is the zscore that has a pvalue of .

For this problem, we have that:

95% confidence level

So , z is the value of Z that has a pvalue of , so .

The lower limit of this interval is:

The upper limit of this interval is:

The 95% (two-sided) confidence interval for the proportion of all dies that pass the probe is (0.37, 0.472)

y=3n + 1

step-by-step explanation:

this is wrong because it says the second number is one less and i added one instead

55% are girls and 45% are boys : ) hope this

step-by-step explanation: