A child spots crackers in a cabinet at an angle of elevation of 50. The crackers are 3.5 ft above the child. To the nearest tenth of a foot, what is the horizontal distance between the child and the crackers?

the horizontal distance between the child and the crackers is 2.9 ft .

Step-by-step explanation:

Here we have , A child spots crackers in a cabinet at an angle of elevation of 50. The crackers are 3.5 ft above the child. We need to find what is the horizontal distance between the child and the crackers . Let's find out:

According to question , we have a right angle triangle with parameters as :

,  Where x is angle of elevation !

We know that  ,

⇒  

⇒  

⇒  

⇒  

⇒  

Therefore , the horizontal distance between the child and the crackers is 2.9 ft .

54 kilometers per hour

step-by-step explanation:

according to rules:

1 km = 1000 meter

which means that 1 meter = 1/1000 km

1 hour = 3600 second [ as 1 hour = 60 min = 60 *60 seconds ]

which means that 1 second = 1/3600 hour

therefore, 1 kilometer/hour =

thus to convert 15 meter per second to kilometer per hour, we multiply 15 to 3.6 kilometer/hour.

15 meter/second=   which is the required answer.