In a study of the progeny of rabbits, Fibonacci (ca. 1170-ca. 1240) encountered the sequence now bearing his name. The sequence is defined recursively as follows.
an + 2 = an + an + 1, where a1 = 1 and a2 = 1.

(a) Write the first 12 terms of the sequence.

The correct answer is 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89.

Step-by-step explanation:

In a study of the progeny of rabbits, Fibonacci encountered the sequence now bearing his name.

The sequence is defined recursively as:

= + , where a1 = 1 and a2 = 1 where n is a natural number.

For n = 0 ; a2 = a0 + a1

⇒ a0 = 0.

For n = 1 ; a3 = a1 + a2 = 1+1

⇒ a3 = 2.

For n = 2 ; a4 = a2 + a3 = 1+2

⇒ a4 = 3.

For n = 3 ; a5 = a3 + a4 = 2+3

⇒ a3 = 5.

For n = 4 ; a6 = a4 + a5 = 3+5

⇒ a6 = 8.

For n = 5 ; a7 = a5 + a6 = 5+8

⇒ a7 = 13.

For n = 6 ; a8 = a6 + a7 = 8+13

⇒ a8 = 21.

For n = 7 ; a9 = a7 + a8 = 21+13

⇒ a9 = 34.

For n = 8 ; a10 = a8 + a9 = 21+34

⇒ a10 = 55.

For n = 9 ; a11 = a9 + a10 = 55+34

⇒ a11 = 89.

Thus the first 12 terms of fibonacci sequence is 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89.

-14

step-by-step explanation:

2x2 – 2(x+4)

=2x2-2（5+4）

=4-2×9

=4-18

=-14

the multiples of 15 are 15, 30,45, 60, 75, 90, 105, 120, 135, 150, 165, 180, 195,   210, 225, 240, 255, 270, 285, 300, 315, 330, 345, 360, 375,   390, 405, 420, 435, 450, 465, 480, 495, 510, 525, 540, 555, 570, 585, 600, 615, 630, 645, 660, 675, 690, 705, 720, and 735.

the factors of 15 are 1, 3, 5, and 15.

hope that , fam!

-une, your fren : )