A clothing store uses feedback cards to get comments from its customers about new items. It recently introduced active wear. Customers who purchased the items were asked to fill out an onlinecomment survey - giving 10% off the next purchase. The data are summarized below. What percentage of customers were at least satisfied with the item(s) purchased Gie, satisfied or very satisfied)y? Response Very satisfied Satisfied Less than fully satisfied Not satisfied Frequency 15 30 12 4

A. 68.9%
B. 49.2%
C. 73.8%
D. 24.6%
E. 26.2%

C. 73.8%

Step-by-step explanation:

Hello!

The store becomes information about customer satisfaction through an online survey. Then the variable of interest is X: customer satisfaction, categorized in "Very satisfied" (V), "Satisfied"(S), "Less than fully satisfied"(L) and "Not satisfied"(N)

You have to calculate the proportion of people that is "At least" satisfied with the items, this means that the customers are "satisfied or more"The categories that enter in this event are "Satisfied" and "Very Satisfied"

To calculate the probability of the customer is at least satisfied you have to add the observations under these two categories and divide it by the sample size:

P(X≥S)=

The percentaje of customers that are at least satisfied with their purchase is 73.77% ≅ 73.8%

I hope it helps!

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