One issue of a journal has 3 full-page ads and
5 half-page ads, generating $6680 in
advertising revenue. The next issue has 4
full-page ads and 4 half-page ads, resulting in
advertising revenue of $6920. Determine the
advertising rates in this journal for full-page
and half-page ads.

x=985 y= 745

Step-by-step explanation:

x=full page

y=half page

3x+5y= 6680

4x+4y= 6920

-4(3x+5y= 6680)

3(4x+4y= 6920)

  -12x-20y= -26,720

+   12x+12y= 20,760

          -8y= -5,960

divide by -8 on both sides

y= 745

plug it in for y in one if the original equations

3x + 5(745) = 6680

3x + 3,725 = 6680

     -3,725    -3,725

3x = 2,955

divide by 3 on both sides

x= 985

h * s * a

h = history teacher

s = science teacher

a =   art teacher.

i see no data table, but just multiply the number of history teachers, science teachers, and art teachers.