2. Triangle XYZ has vertices X(-1, -2), Y(6, -3) and Z(2,-5).
Find the vertices of AXY'Z' after a translation of 2 units left
and 1 unit up.
Use a table. Add 2 to the x-coordinates and 1 to the
y-coordinates.
Vertices of
Η ΔΧΥΣ
i
Vertices of
(ΚΕΕ2)
Υ ΔΧΥΖΗ
X(-1, -2) (-1+(-2), –2 + 1) | X(-3,-1)
Y(6,-3) (6 +(-2), -3 + 1) Y(4,-2)
Z(2,-5) (2+(-2), -5 + 1) z'(0, –4)
So, the vertices of AX'Y'Z' are X'(-3, -1), Y'(4, -2), and Z'(0, –4).

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet