PLZ HELP ME my teacher be buggin

2.

We have a transversal across parallel lines so we get the usual array of congruent and supplementary angles.  We just have to figure out which is which, and the diagram, even though not to scale, makes it pretty obvious.

Angle x isn't the same as the 40° angle so it must be its supplement.

C 140°

3.

r=1.2, h=2.9, V = (1/3) πr²h

Nothing hard here, we just plug in the numbers,

V = (1/3) π (1.2)² (2.9) ≈ 4.37310

B. 4.4 cubic inches

4.

Dilation by .5 makes a similar triangle, and reflection is an isomorphism (i.e. it doesn't change the size or shape) so the answer is

B similar not congruent

5.

The corresponding interior and exterior angles of a triangle form a linear pair, so supplementary angles. x=180-110 = 70°

A 70°

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet