In 2011, New York City has a total of 11,232 motor vehicle accidents that occurred on Monday through Friday between the hours of 3 p. m. and 6 p. m. (new York State Department of Motor Vehicles website, October 24, 2012). This corresponds to mean of 14.4 accidents per hour.

a. Compute the probability of no accidents in a 15-minute period.

b. Compute the probability of at least one accident in a 15-minute period.

c. Compute the probability of four or more accidents in a 15-minute period.

Step-by-step explanation:

a. #We notice this is a Poisson probability function expressed as:

x-number of occurrences in a given interval.

-mean occurrences of the event

-The mean is calculated as:

#the probability of no accidents in a 15-minute period is :

Hence, the probability of no accident in a 15-min period is

b. The the probability of at least one accident in a 15-minute period. is calculated as:

Hence,  the probability of at least one accident in a 15-minute period is

c. The probability of four or more accidents in a 15-minute period is calculated as:

Hence,the probability of four or more accidents in a 15-minute period. is  0.9997

x = 17

step-by-step explanation:

1st step: isolate x.

24 - 3x = -27

-24         -24

-3x   =   -51

2nd step: divide.

-3x     =   -51

  3             3

  x       =     17

hope this

median is the value separating the higher half of a data sample, a population or probablity distribution from the lower half.

step-by-step explanation:

say you have 3,8,7,3,1,9,8 order them from lowest to highest

if orderd it would be 1,3,3,7,8,8,9 now you take away from the lowest and the highest until you end up in the middle.

so you would remove the 1 and 9 leaving you with 5 digits remaining

when you've reached the middle that would be your answer so in this case the answer is 7

if there were two numbers left say 7 and 5 you'd and them together so 12 then divide by 2 witch would equal 6 so the answer would be 6

good luck on that project hoped i you at all