Topic: Choosing ping-pong balls without replacement. There are 6 white and 3 orange ping-pong balls in a brown paper bag. Two balls are randomly chosen. Enter your answers as fractions. (The "Preview" simply displays your answer in nice mathematical text. It does not mean that your answer is either right or wrong.) a) How many total balls are in the bag? Preview b) What is the probability that the 1st ball is orange? P(1st = orange) = Preview c) What is the probability that the 2nd ball is also orange, given that the 1st ball was orange? P(2nd = orange | 1st = orange) = Preview d) What is the probability that both the 1st and the 2nd balls are orange?

a. 9

b. 1/3

c. 1/4

d. 1/12

Step-by-step explanation:

White balls = 6

Orange balls = 3

a. Total number of balls = 6 + 3

= 9

Total balls in bag = 9

b) Probability that the first ball is orange

= No. of orange balls / Total no. of balls

= 3 / 9

= 1 / 3

c) To give the required probability

If one ball being the orange ball has been taken out then the remainder are,

Total balls = 8

If Orange balls = 2

Therefore the probability that the 2nd ball is also orange, given that the 1st ball was orange will be denoted by,

= P(2nd ball|1st orange)

= 2 / 8

= 1 / 4

d) To give the probability that both the 1st and the 2nd balls are orange you multiple their probabilities.

Probability = 1 / 3 * 1 / 4

= 1 / 12

step-by-step explanation:

i found the life tables for the year 2012. 

life table of males at age 30. probability of dying between ages x and x+1

total population:  

29–30 . . . . . . . . . . . . 0.001030

30–31 . . . . . . . . . . . . 0.001061

males:  

29–30 . . . . . . . . . . . . 0.001420

30–31 . . . . . . . . . . . . 0.001448

white population

29–30 . . . . . . . . . . . . 0.001005

30–31 . . . . . . . . . . . . 0.001037

white males

29–30 . . . . . . . . . . . . 0.001372

30–31 . . . . . . . . . . . . 0.001399

non hispanic white population

29–30 . . . . . . . . . . . . 0.001083

30–31 . . . . . . . . . . . . 0.001116

non hispanic white males

29–30 . . . . . . . . . . . . 0.001477

30–31 . . . . . . . . . . . . 0.001503

jacob, non hispanic white male. 30 years old.

probability that jacob lives to be 30 years old. 

since the given probabilities are probabilities of dying, i think we simply subtract it from 1 to get the probability of living. we will use the probability of non hispanic white male.

                                          probability of living to be 30 y.o.

29 - 30 : 1 - 0.001477 = 0.998523

30 - 31 : 1 - 0.001503 = 0.998497