You want to create an 80% confidence interval for the average age of people who attend U of O football games. You take a sample of 100 attendees and find the average age to be 43.7 years old with a standard deviation of 7 years. Find the value of t* for this confidence interval. Do not round your answer. Write your answer in decimal form, not as a fraction or percent.

80% confidence interval for the average age of people who attend U of O football games is [42.795 , 44.604].

Step-by-step explanation:

We are given that a sample of 100 attendees and find the average age to be 43.7 years old with a standard deviation of 7 years.

So, the pivotal quantity for 80% confidence interval for the population average start up cost is given by;

          P.Q. = ~

where, = sample average age = 43.7 years old

             = sample standard deviation = 7 years

            n = sample of attendees = 100

             = population average age of people

So, 80% confidence interval for the average age of people, is ;

P(-1.2915 < < 1.2915) = 0.80

P(-1.2915 < < 1.2915) = 0.80

P( < < ) = 0.80

P( < < ) = 0.80

80% confidence interval for = [ ,  ]

                                                 = [ , ]

                                                 = [42.795 , 44.604]

Therefore, 80% confidence interval for the population average age of people who attend U of O football games is [42.795 , 44.604].

is should be y = 5x

step-by-step explanation:

correct me if im wrong