The March utility bills (in dollars) of 30 homeowners are listed below. 44 38 41 50 36 36 43 42 49 48 35 40 37 41 43 50 45 45 39 38 50 41 47 36 35 40 42 43 48 33 Using these given data to construct a frequency distribution using 5 classes and using 33 as the lower class limit of the first class.

Step-by-step explanation:

What we will do is create a table with the data they give us, the first thing will be to organize it from smallest to largest, like this:

33, 35, 35, 36, 36, 36, 37, 38, 38, 39, 40, 40, 41, 41, 41, 42, 42, 43, 43, 43, 44, 45, 45, 47, 48, 48, 49, 50, 50, 50

Now we know that the smallest number is 33 and the largest is 50, to create 5 ranges, we will calculate the difference and divide by 5.

(50 - 33) / 5 = 3.4

Therefore we will make ranges of 3 and 4, values, like this

Rank 1: 33 - 36

Rank 2: 37 - 39

Rank 3: 40 - 43

Rank 4: 44 - 46

Rank 5: 47 - 50

We will calculate the frequency distribution of values in each range:

Rank 1: 6

Rank 2: 4

Rank 3: 10

Rank 4: 3

Rank 5: 7

x = 17

step-by-step explanation:

1st step: isolate x.

24 - 3x = -27

-24         -24

-3x   =   -51

2nd step: divide.

-3x     =   -51

  3             3

  x       =     17

hope this

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!