A family has three children. If the genders of these children are listed in the order they are born, there are eight possible outcomes: BBB, BBG, BGB, BGG, GBB, GBG, GGB, and GGG. Assume these outcomes are equally likely. Let X represent the number of children that are girls. Find the probability distribution of X.

P(X = 0) = 1/8

P(X = 1) = 3/8

P(X = 2) = 3/8

P(X = 3) = 1/8

Step-by-step explanation:

The family may have zero, one, two or three children that are girls (X = 0, 1, 2, 3).

Out of the 8 possible outcomes for having three children, there is 1 with zero girls,  3 with one girl, 3 with two girls, and 1 with 3 girls. The probability distribution of X is:

P(X = 0) = 1/8

P(X = 1) = 3/8

P(X = 2) = 3/8

P(X = 3) = 1/8

first one is a: renaming a fraction. second one is c: de-c

step-by-step explanation:

my explanation is that these were the answers on edg : )

4 + 5 7/9= 9 7/9

step-by-step explanation: