Consider the following differential equation to be solved by undetermined coefficients. y(4) − 2y''' + y'' = ex + 1 Write the given differential equation in the form L(y) = 0, where L is a linear operator with constant coefficients. If possible, factor L. (Use D for the differential operator.) Incorrect: Your answer is incorrect. y = ex + 1 Find a linear differential operator that annihilates the function g(x) = ex + 1. (Use D for the differential operator.) Solve the given differential equation by undetermined coefficients. y(x) =

The general solution is

     +

Step-by-step explanation:

Step :1:-

Given differential equation  y(4) − 2y''' + y'' = e^x + 1

The differential operator form of the given differential equation

comparing f(D)y = e^ x+1

The auxiliary equation (A.E) f(m) = 0

The roots are m=0,0 and m =1,1

complementary function is

Step 2:-

The particular equation is    

P.I =

P.I =

P.I =

applying in integration u v formula

=

again integration  

The general solution is

      +

answer: i oofed

step-by-step explanation:

oofed=wow

42%

step-by-step explanation:

we know,

total people = 60

total males = 25

percentage of males

= 25/60 × 100

= 25/6 × 10

= 25/3 × 5

= 125 / 3

= 41.

rounding of = 42%

happy to

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