The equation of a circle is x2 + y2 + 6x + 4y + 10 = 1. What is this equation written in its standard form?

A) (x + 3)2 + (y + 2)2 = 4
B) (x + 6)2 + (y + 4)2 = 4
C) (x + 6)2 + (y + 4)2 = 10
D) (x + 3)2 + (y + 2)2 = 10

answer : A

Step-by-step explanation:

hello :

x² + y² + 6x + 4y + 10 = 1

(x²  + 6x )+(y²+ 4y) + 10 = 1

(x²  + 6x+9-9 )+(y²+ 4y+4-4) + 10 = 1

(x²  + 6x+9)-9 +(y²+ 4y+4)-4 + 10 = 1

(x+3)²+(y+2)² = 4     answer : A

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752