The height of a projectile in the air t seconds after it is shot can be modeled by the function y = -16t^2 + 3200t + 2, where t and y are measured in feet. What is the maximum height that the projectile reaches?

160002 feet

Step-by-step explanation:

y(t)=-16t^2+3200t+2

We need y’ to find a maximum

y’(t)=-32t+3200

y’(t)=0 if t=100

Notes that y’(t)>0 if t<100, and fot t>100 y’(t)<0. Now we can conclude that y(t) has maximum in t=100

Y(100)=-16*10000+3200*100+2

Y(100)=160002 feet

answer: this doesnt make any sense especially the photo.

step-by-step explanation:

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.