You can use the equation d = 16t^2 (note: t is raised to the second power or squared) to determine the time t in seconds that it takes a dropped object to fall a distance of d feet. How long (in seconds) does a fall of 224 feet take? Round your answer to the nearest tenth. *

The time the object takes to fall on the ground from 224 feet is 3.74 s.

Step-by-step explanation:

In this case we have a known quantity, the distance of the fall that is 224 feet and a equation that represents the motion of this fall that is d = 16t^2. We wish to find the time it'll take this object to fall, so we can solve this equation for t. It goes as follows:

d = 16t^2

d/16 = t^2

t^2 = d/16

t = \sqrt(d/16)

t = [\sqrt(d)]/4 = [\sqrt(224)]/4 = 14.97/4 = 3.74 s

where \sqrt is the square root of the number.

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

step-by-step explanation:

6.48/4 4 goes into 6.48 1.62 times