An observation deck extends 120 feet out above a valley. The deck sits 70 feet above the valley floor. If an object is dropped from the observation deck, its height h in feet, after t seconds, is given by h equals negative 16 t squared plus 70. How long will it take for the object to be 6 feet above the valley floor? It will take seconds for the object to be 6 feet above the valley floor.

2

Step-by-step explanation:

The height formula given is:

h = -16t^2 + 70

That means the object will be initially (t=0) at the height 70 feet, from where it will be dropped.

If we want to know the time when the object will be at height 6 feet, we just need to use h=6 in the equation, and then calculate the value of t:

6 = -16t^2 + 70

16t^2 = 64

t^2 =4

t = 2 s

So, it will take 2 seconds for the object to be 6 feet above the valley floor.

i am unable to solve this problem

step-by-step explanation:

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the miami heat median: 1.47

the iqr of this data is 0.05