An object is dropped from the top of a tower with a height of 1120 feet. Neglecting air resistance, the height of the object at time t seconds is given by the polynomial -16t^2+1120 find the height of the object at t=7 seconds ight of the object at time t seconds is given by the polynomial negative 16 t squared plus 1120. Find the height of the object at t equals 7 seconds

The height of the object at t=7 seconds is 336 feet.

Step-by-step explanation:

Given,

An object is dropped from the top of a tower with a height of height of 1120 feet.

The height of the object at time t second is given by the polynomial

h(t)= -16t² +1120

To find the height, we put the value of t=7 in the above equation

h(7)= - 16(7)²+1120

    = 336 feet.

The height of the object at t=7 seconds is 336 feet.

Height of the object after 7 seconds would be 336 feet.

Step-by-step explanation:

Given:

Height of the tower = 1120 ft

We need to find the height of the object after 7 seconds.

Solution:

To find the height of the object after 7 seconds we will substitute t = 7 secs

So we can say that;

Hence We can say that;

Height of the object after 7 seconds would be 336 feet.

answer:

the position of equilibrium will shift to the left.

step-by-step explanation:

the general equation for the dissociation of a weak base is

b + h₂o   ⇌   bh⁺ + oh⁻

according to le châtelier's principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

if you apply a stress by adding more bh⁺ or oh⁻,   the system will respond by moving in a direction that gets rid of the added ions.

the position of equilibrium will shift to the left, forming more of the undissociated base.

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step-by-step explanation: