The radius of the circle is increasing at a rate of 2 meters per minute and the sides of the square are increasing at a rate of 1 meter per minute. When the radius is 6 meters, and the sides are 24 meters, then how fast is the AREA outside the circle but inside the square changing?

Change in area=24-48

Step-by-step explanation:

Let s will be the side of square and r will be the radius of circle.

Then two given conditions are

1)dr/dt=2 m/s

2)ds/dt=1 m/s

Area enclosed=(Area of square)-(Area of circle)

Area of square=

Area of circle=

Area enclosed=

dA/dt=2r(dr/dt)-2s(ds/dt)

At s=24,and r=6

dA/dt=2()(6)(2)-2(24)(1)

Change in area=24-48

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

answer: the answer is simply nothing.

step-by-step explanation: because there is no ending to this question

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