Faelyn grouped the terms and factored the GCF out of the groups of the polynomial 6x4 – 8x2 + 3x2 + 4. Her work is shown.

Step 1: (6x4 – 8x2) + (3x2 + 4)

Step 2: 2x2(3x2 – 4) + 1(3x2 + 4)

Faelyn noticed that she does not have a common factor. Which accurately describes what Faelyn should do next?

Faelyn should realize that her work shows that the polynomial is prime.
Faelyn should go back and regroup the terms in Step 1 as (6x4 + 3x2) – (8x2 + 4).
In Step 2, Faelyn should factor only 2x out of the first expression.
Faelyn should factor out a negative from one of the groups so the binomials will be the same.
Mark this and return

Faelyn should go back and regroup the terms in Step 1 as (6x4 + 3x2) – (8x2 + 4).

Step-by-step explanation:

The groups of the polynomial that Faelyn was trying to factorize is expressed as

6x4 – 8x2 + 3x2 + 4.

In her first step, she does not have a common factor. Therefore, the next thing that Faelyn should do is that

Faelyn should go back and regroup the terms in Step 1 as (6x4 + 3x2) - (8x2 + 4). In doing this, it becomes

3x2(2x2 - 1) - 4(2x2 - 1)

The common factor here is 2x2 - 1. It becomes

(2x2 - 1)(3x2 - 4)

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

0.6

39mph

step-by-step explanation: