1 point) A computer retail store has 11 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail store or the buyer, 3 of the computers in stock have defective hard drives. Assume that the computers are selected at random. (a) In how many different ways can the 3 computers be chosen

165 ways

Step-by-step explanation:

The process of selection is done by using the combination formula for selection. If given "n" items and we are to choose "r" items from this given "n", the formula to use is denoted by:

nCr. = n! /(n-r)! × r!

Where

n! = n * (n-1) * (n-2)... *3*2*1.

In this case the number of items given = 11

And the number of items to be chosen = 3,

Hence the number of ways to do this = 11C3= 11!/(11-3)! × 3!

=165 ways.

24/56=hx^7

step-by-step explanation:

well what you have to do is divide 84 by 6 so theanswer

step-by-step explanation:

84 divided by 6 = 14

and that lightbulb changing party must be freaking lit!