A university is composed of five schools. The enrollment in each school is given:
Humanities: 1050
Social Science: 1410
Engineering: 1850
Business: 2540
Education: 3580
There are 300 new computers to be apportioned to another school's computer labs according to their respective enrollments. Using Hamilton's method, what would be the standard divisor for this situation?

34.767 enrollments/computer

Step-by-step explanation:

According to the Hamilton's method, the standard divisor, D, is determined by dividing the number of enrollments in all schools by the number of new computers available:

The standard divisor for this situation should be 34.767 enrollments/computer.

well my understanding of this question is they want you to use the y=14.1x -2.3 and put the coordinates they gave you onto the line segment of   y=14.1x -2.3

step-by-step explanation:

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!