Suppose a shipment of 400 components contains 68 defective and 332 non-defective computer components. From the shipment you take a random sample of 25. When sampling with replacement (so that the p = probability of success does not change), note that a success in this case is selecting a defective part. The mean of this situation is?

The mean of this situation is 4.25

Step-by-step explanation:

Given,

the number of computer components = 400

No of defective computer components=

Probability of selecting a defective computer ==0.17

Mean of this situation = n×p

where n is no of random sample

Therefore, Mean= 25×0.17=4.25

not enough information

step-by-step explanation:

we cannot know this, because the other students could have handed out 10 flyers, or they could have handed out 100. one way, the mean would go up, and another way, the mean would go down.