Find a slope and y- interception of the line that is parallel to y = -x - 1 and passes through the point (5, -5).

y = 0

Step-by-step explanation:

hello :

 note :  the point-slope formula is :

y - y_1 = m(x - x_1)  for the line  passes by the point A(x_1 ; y_1 )  , the slope is : m

in this exercice : m =- 1 parallel to y = -x - 1 (same slope -1)

x_1 = 5  and y_1 = - 5

an equation is : y+5 = - (x-5)

y- interception of the line when : x=0

y+5 = - (0-5)

y = 0

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

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