The hypotenuse of a 45°-45°-90° triangle measures 22 StartRoot 2 EndRoot units.

A right triangle is shown. The length of the hypotenuse is 22 StartRoot 2 EndRoot 2 units. The lengths of the other 2 sides are congruent.

What is the length of one leg of the triangle?

11 units

11 StartRoot 2 EndRoot units

22 units

22 StartRoot 2 EndRoot units

Length of the other leg is 22 units

Step-by-step explanation:

Hypotenuse² = x² + x²

(22√2)² = 2x²

⇒ x² = 22 × 22 × 2/2 = 22 × 22

∴ x = 22 units

i dont get the question

step-by-step explanation:

step-by-step explanation:

this can be solved first with pythagorean theorem, which tells us to square both legs of the triangle and sum it. this will be equal to the square of the hypotenuse.

the hypotenuse is the side "opposite" the 90 degree angle, which is x.

so we can write using pythagorean theorem,

simplifying:

to further simplify this radical, we need to use the property  

thus