I have a coil of steel that is 48 inches wide. The weight of the coil is 10.800 kegs. If I cut the coil a width of 0.5 inches how much will the 0.5 inch coil weigh. Can you show me an example on how to figure this problem out.

0.1125 kg

Step-by-step explanation:

Step 1:

Let us assume that 48 inches of coil of steel weighs 10.800 kg.

We have to find the weight of 0.5 inch coil.

Step 2:

In this problem we assume that it is given in direct relationship.

Therefore, Problem becomes

48 inches weigh 10.8 kg

0.5 inches weigh X kg

(48 / 0.5) = ( 10.8 / X)

X =  (10.8 × 0.5) / 48

X =  0.1125 kg

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below:

ummm seems that u didnt post the attachement !